Problem Detail: How would I solve the following can anyone help me.I know MIPS is basically how many instruction the processor can do per second but what should I do? Assume that we are receiving a message across a network using a modem with a rate of 56,000 bits/second. Furthermore assume that we are working on a workstation with an instruction rate of 500 mips. How many instructions can the processor execute between the receipt of each individual bit of the message?
Asked By : Fernando Martinez
Answered By : Ran G.
There are not enough details in the question. Yuval’s answer gives the basic arithmetic answer. I’ll just add that usually modems do not transfer the information “as-is” but encode it (see Asynchronous serial communication). The most common encoding is 8N1, which means 10 symbols are sent per 1 byte of the message. The baud rate (56,000) is the number of symbols per second, rather than the number of bits per second. So 8 bits of the message take 10 symbols, that is 1/5600 second. 1 bit takes 1/44800 sec. During that time, with 500MIPS you have $approx 11200$ instructions.
(of course, if the rate is indeed 56000 bits/sec, then the 8/10 factor is not necessary.)
(of course, if the rate is indeed 56000 bits/sec, then the 8/10 factor is not necessary.)
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Question Source : http://cs.stackexchange.com/questions/10561
