instances of 3-SAT in which every variable occurs three times are always satisfiable (this is an immediate corollary of Hall’s Theorem), while it is NP-hard to decide the satisfiability of 3-SAT instances in which every variable occurs four times
so apparently when variables appear 3 times it’s an easy problem (?). But the following two references seem to say something else: From here, http://www.csie.ntu.edu.tw/~lyuu/complexity/2008a/20080403.pdf,
3sat is NP-complete for expressions in which each variable is restricted to appear at most three times, and each literal at most twice.
and http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.319.8796&rep=rep1&type=pdf Lemma 5:
The SAT-3 problem is NP-complete even when each variable appears 3 times.
So is this problem NP-complete for when variables appear 3 times or 4 times? I’m pretty confused.
Asked By : user2520385
Answered By : Tom van der Zanden
Let r,s-SAT denote the class of instances with exactly r variables per clause and at most s occurrences per variable. […] Theorem 2.1. Boolean satisfiability is NP-complete when restricted to instances with 2 or 3 variables per clause and at most 3 occurrences per variable. […] Theorem 2.4. Every instance of r,r-SAT is satisfiable.
The reason there’s no conflict is that you need to allow 2 or 3 literals per clause to make 3-SAT $NP$-complete when restricted to at most 3 occurrences per variable. The trivially satisfiable bit only kicks in when you have exactly 3 literals per clause and at most 3 occurrences per variable.
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Question Source : http://cs.stackexchange.com/questions/48442