Problem Detail: A computer has 2 GB of RAM of which the operating system occupies 256 MB. The processes are all 128 MB (for simplicity) and have the same characteristics. If the goal is 99% CPU utilization, what is the maximum I/O wait that can be tolerated? My professor said that there are 14 processes in the memory before proceeding with the solution. Why are there 14 processes?
Asked By : Jane D.
Answered By : Yuval Filmus
You want all processes to fit in memory. If there are $N$ processes, then together with the OS they take up $256+128N$ megabytes. Since there is only room for $2048$ megabytes, we need $256+128N leq 2048$. Dividing by $128$, this is $N+2 leq 16$.
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