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$L_{ge5} = left { left< M right> : M text{ accepts at least 5 strings} right} $
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$L_{<5} = left { left< M right> : M text{ accepts fewer than 5 strings} right}$
Are these recursive, R.E., or not R.E. sets (languages)? I would say that they are not recursive, based on applications of Rice’s Theorem.
- For the first case $L_{e}= left { left< M right> :L(M)= emptyset right } notin L_{ge5} $ and $L_{ge5}$ are not empty. For example, I define $L= left { left< M right> : M text{ accepts all palindromes} right }$, which is not finite set and accepts an infinite number of strings.
- For the second case I would do the same thing. I have $L_{e}=left{ left< M right>: L(M)= emptyset right} in L_{<5}$ and $L=left{ left< M right>:M text{ accepts all palindromes} right} notin L_{<5} $
So I would say that both are not recursive. Is my reasoning correct? Now about the R.E. of the languages I don’t have an idea of how I can prove it, this should be the beginning (if L is not RE it can’t be recursive), how can I check if they are RE or not? From the definition: “$L$ is RE $iff$ there exists a TM $M$ that accepts $L$”, so I just have to define a TM that accepts each language?
Asked By : newbie
Answered By : jmite
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