Asked By : Nemo
Answered By : Ricky Demer
of making at least 1/2 of Y’s entries equal 1. That can be derandomized
by sequentially setting each variable to [something that forces at least
as many of Y’s entries to 1 as it forces to 0, with ties broken arbitrarily].)
By this paper‘s proof of Theorem 5.6, for all real
numbers $epsilon$, if $0 < epsilon$ then the promise problem Input: instance of your problem in which each row of A has exactly 4 ones
must output YES if: there is an assignment which makes more than 1-$hspace{.03 in}epsilon$ of Y’s entries equal 1
must output NO if: for every assignment, less than (1/2)$hspace{.03 in}$+$hspace{.03 in}epsilon$ of Y’s entries equal 1 is NP-hard.
When parameterized by the number of zeros in Y, your problem is obviously in W$[hspace{-0.02 in}$P$]$O,
but I don’t know anything else about your problem’s parameterized complexity. This paper gives a possible try for your problem,
although it looks like it’s just a student’s “3rd Year Project Report”.
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